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SL 2.4—Features of a graph

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  1. Question 1

    A candle is 20 cm tall when first lit. It burns down at a constant rate of 2.5 cm per hour. The function L(t)=20−2.5t models the length of the candle (in cm) after t hours. What is the domain of L(t) in the context of this problem?
    No clue? Show me the answer
    Correct answerCorrect!Incorrect
    A0≤t≤8

    Step-by-step walkthrough

    Choose a solution method

    Method #1Direct approach

    Step 1: Identify the context constraint

    The candle starts at t=0 and stops burning when it reaches zero length. We need to find when L(t)=0.

    Step 2: Solve for the endpoint

    Set L(t)=0: 20−2.5t=0⟹t=2.520​=8 So the candle is fully burned after 8 hours.

    Step 3: Identify the domain

    Since t represents time, it cannot be negative, and the model is only valid until the candle is gone. The domain is 0≤t≤8.

    Step 4: Select the correct answer

    The domain in context is 0≤t≤8, which corresponds to the first option.

    Method #2Process of Elimination

    Step 1: Identify what is being asked

    We need the domain — the valid set of input values (t) — constrained by the physical context of the candle burning.

    Step 2: Eliminate '$0 \leq t \leq 20$'

    At t=20, L(20)=20−50=−30 cm, which is physically impossible. The candle cannot have negative length, so this interval is too large.

    Step 3: Eliminate '$t \geq 0$'

    This ignores the upper boundary. The candle only exists for a finite time — allowing t to grow without bound is not physically meaningful.

    Step 4: Eliminate '$0 \leq L \leq 20$'

    This describes the range (output values L), not the domain (input values t). The question specifically asks for the domain.

    Step 5: Select the correct answer

    The candle burns from t=0 to t=8 (when L=0), so the correct domain is 0≤t≤8.

  2. Question 2

    A candle is 20 cm tall when first lit and burns at 2.5 cm per hour, modelled by L(t)=20−2.5t for valid t. What is the range of L(t) in the context of this problem?
    No clue? Show me the answer
    Correct answerCorrect!Incorrect
    A0≤L≤20

    Step-by-step walkthrough

    Choose a solution method

    Method #1Direct approach

    Step 1: Recall the definition of range

    The range is the set of all possible output values (L-values) produced by the function over its valid domain.

    Step 2: Find the outputs at the domain boundaries

    At t=0: L(0)=20 cm (full candle). At t=8: L(8)=20−20=0 cm (fully burned). Since L(t) is linear and decreasing, all values between 0 and 20 are achieved.

    Step 3: State the range

    The candle length varies from 20 cm down to 0 cm, so the range is 0≤L≤20.

    Step 4: Select the correct answer

    The range of L(t) in context is 0≤L≤20.

    Method #2Process of Elimination

    Step 1: Identify what is being asked

    We need the range — the valid set of output values L — given the physical context of a burning candle.

    Step 2: Eliminate '$0 \leq t \leq 8$'

    This is the domain (input values t), not the range (output values L). It does not answer the question.

    Step 3: Eliminate '$L \geq 0$'

    This correctly excludes negative lengths but ignores the upper bound. The candle cannot be longer than 20 cm (its starting length), so L≤20 must also be included.

    Step 4: Eliminate '$-\infty < L \leq 20$'

    This allows negative lengths, which is physically impossible for a candle. The range cannot extend below zero.

    Step 5: Select the correct answer

    Only 0≤L≤20 correctly captures all physically valid output values of the candle-length function.

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← Previous topicSL 2.3—Graph of a functionNext topic →SL 2.5—Modelling functions
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