Question 1
A student takes out a loan of $\$12{,}000$ to purchase a motorcycle. The loan has a nominal annual interest rate of , compounded monthly, and is to be repaid over 3 years with equal monthly payments. What is the monthly payment amount, correct to the nearest cent?No clue? Show me the answer
Correct answer
Correct!
IncorrectStep-by-step walkthrough
Choose a solution method
Method #1Approach 1Step 1: Identify the Variables
Principal: . Annual interest rate: , so monthly rate: . Number of payments: .
Step 2: Apply the Loan Payment Formula
Step 3: Calculate the Compounding Factor
. This is the key exponential term accounting for compound interest over 36 months.
Step 4: Complete the Calculation
Step 5: State the Answer
The monthly payment is \381.60$. Using a GDC TVM Solver with N = 36, I% = 9, PV = 12000, FV = 0, P/Y = 12, C/Y = 12 and solving for PMT confirms this result.
Method #2Approach 2Step 1: Identify What Is Being Asked
We need the equal monthly payment for a \12{,}0009%$ annual interest compounded monthly over 3 years. The correct approach uses the compound interest loan payment formula, not simple interest.
Step 2: Eliminate $\$333.33$
**\333.33$12{,}000$ by 36 payments. This ignores interest entirely and is incorrect for any interest-bearing loan.
Step 3: Eliminate $\$360.00$
**\360.009%$12{,}000$1{,}080$) and dividing by 36, which uses simple interest logic. Real loans use compound interest, so this underestimates the true payment.
Step 4: Eliminate $\$392.44$
**\392.440.090.0075$) in the formula, which significantly overstates the periodic rate and inflates the payment.
Step 5: Select the Correct Answer
**\381.60r = 0.0075n = 36$, giving the only accurate monthly payment.
Question 2
The table below shows the first two rows of an amortization schedule for a loan repaid monthly. Based on this information, what is the remaining balance after payment 2?
Payment # Payment Interest Paid Principal Paid Remaining Balance 1 \310.00$ \100.00$ \210.00$ \19{,}790.00$ 2 \310.00$ ? ? ? No clue? Show me the answer
Correct answer
Correct!
IncorrectStep-by-step walkthrough
Choose a solution method
Method #1Approach 1Step 1: Identify the Monthly Interest Rate
From payment 1, the original balance must have been \20{,}000= $210.00= $19{,}790.00= $20{,}000r = \dfrac{100}{20{,}000} = 0.005$ per month.
Step 2: Calculate Interest for Payment 2
Interest in payment 2 = 19{,}790.00 \times 0.005 = \98.95$.
Step 3: Calculate Principal Paid in Payment 2
Principal paid in payment 2 = 310.00 - 98.95 = \211.05$.
Step 4: Calculate Remaining Balance After Payment 2
New balance = 19{,}790.00 - 211.05 = \19{,}578.95$.
Step 5: State the Answer
The remaining balance after payment 2 is \19{,}578.95$. Notice the balance decreases slightly more in period 2 than period 1 because less interest was charged.
Method #2Approach 2Step 1: Identify the Key Calculation Required
We must find the balance after payment 2 by computing: Interest balance rate, then Principal payment interest, then New balance old balance principal paid. The monthly rate is .
Step 2: Eliminate $\$19{,}579.05$
**\19{,}579.0519{,}790 \times 0.005 = 98.9598.90$98.95$0.10$.
Step 3: Eliminate $\$19{,}580.00$
**\19{,}580.00$210.00$ (the period-1 principal) again in period 2, ignoring that the interest changes each period. The principal paid increases slightly each period.
Step 4: Eliminate $\$19{,}481.00$
**\19{,}481.00$310.00$ from the balance instead of only the principal portion, which confuses the total payment with the principal reduction.
Step 5: Select the Correct Answer
**\19{,}578.95= $98.95= $211.05= 19{,}790.00 - 211.05 = $19{,}578.95$.