DP Math AA · HL / SL · Number and Algebra

SL 1.9—Binomial theorem where n is an integer

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  1. Question 1

    What is the value of (49​)?
    No clue? Show me the answer
    Correct answerCorrect!Incorrect
    B126

    Step-by-step walkthrough

    Choose a solution method

    Method #1Direct approach

    Step 1: Write the formula

    Use the binomial coefficient formula: (49​)=4!⋅5!9!​

    Step 2: Cancel common factors

    Write out only the factors that don't cancel: 4×3×2×19×8×7×6​

    Step 3: Compute numerator and denominator

    Numerator: 9×8×7×6=3024. Denominator: 4!=24.

    Step 4: Divide to get the answer

    243024​=126 So (49​)=126.

    Method #2Process of Elimination

    Step 1: Identify what is being asked

    We need to compute (49​) using the formula r!(n−r)!n!​ with n=9, r=4.

    Step 2: Eliminate 36

    36 would equal (29​)=29×8​=36, not (49​). This is the wrong value of r.

    Step 3: Eliminate 84

    84 equals (39​)=69×8×7​=84. Again, this uses r=3, not r=4.

    Step 4: Eliminate 210

    210 equals (410​) or (610​), not (49​). This is an off-by-one error in n.

    Step 5: Select the correct answer

    126 is correct since (49​)=4!9×8×7×6​=243024​=126.

  2. Question 2

    Which row of Pascal's triangle gives the binomial coefficients for the expansion of (a+b)6?
    No clue? Show me the answer
    Correct answerCorrect!Incorrect
    B1  6  15  20  15  6  1

    Step-by-step walkthrough

    Choose a solution method

    Method #1Direct approach

    Step 1: Identify the required row

    The expansion of (a+b)n uses row n of Pascal's triangle. For (a+b)6, we need row 6, which has 7 entries.

    Step 2: Compute the entries using $\binom{6}{r}$

    The entries are (06​),(16​),…,(66​), which equal 1,6,15,20,15,6,1.

    Step 3: Match to the correct option

    The sequence 1,6,15,20,15,6,1 matches the second option. Notice the symmetry: (r6​)=(6−r6​).

    Method #2Process of Elimination

    Step 1: Identify what is being asked

    We need the row of Pascal's triangle corresponding to n=6, which must have exactly 6+1=7 entries.

    Step 2: Eliminate the row with 6 entries

    1 5 10 10 5 1 has only 6 entries — this is row 5, used for (a+b)5, not (a+b)6.

    Step 3: Eliminate the row with 8 entries

    1 7 21 35 35 21 7 1 has 8 entries — this is row 7, used for (a+b)7.

    Step 4: Eliminate the incorrect 7-entry row

    1 6 12 8 12 6 1 has 7 entries but the values are wrong. For example, (26​)=15=12. These appear to be powers of 2, not binomial coefficients.

    Step 5: Select the correct answer

    1 6 15 20 15 6 1 is row 6 of Pascal's triangle, confirmed by (26​)=15 and (36​)=20.

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← Previous topicSL 1.8—Sum of infinite geo sequenceNext topic →AHL 1.10—Perms and combs, binomial with negative and fractional indices
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