DP Geography · HL / SL · Option D Geophysical Hazards

D.5 Synthesis, Evaluation, and Skills

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  1. Question 1

    A major earthquake ruptures a subduction megathrust off a densely populated coastline. Which sequence correctly describes the cascade of hazards that can follow from this single seismic event?
    No clue? Show me the answer
    Correct answerCorrect!Incorrect
    AGround shaking → vertical seafloor displacement → tsunami → coastal inundation and infrastructure destruction

    Step-by-step walkthrough

    Choose a solution method

    Method #1Cascade Tracing

    Step 1: Identify the initiating event and the key mechanism

    The primary hazard is the earthquake itself. For a tsunami to be generated, the critical link is vertical displacement of the seafloor, which pushes the overlying water column upward, setting long-wavelength waves in motion.

    Step 2: Apply the tsunami generation conditions

    Tsunamigenic earthquakes require a magnitude of roughly M 7.0+, a dip-slip (vertical) fault motion, and a shallow epicentre beneath or near the ocean. Strike-slip faults displace rock horizontally and rarely generate significant tsunamis.

    Step 3: Trace the wave through the ocean system

    In deep water the waves travel at high speed (v=gd​) with low amplitude; as they enter shallow coastal water, speed decreases and wave height amplifies dramatically, causing coastal inundation.

    Step 4: Select the correct cascade pathway

    The correct sequence moves from ground shaking → vertical seafloor displacement → tsunami radiating across the ocean → coastal inundation and destruction of infrastructure, exactly matching the subduction-zone mechanism described.

    Method #2Process of Elimination

    Step 1: Identify what the question is testing

    The question asks for the physically accurate cascade sequence following a subduction-zone megathrust earthquake, requiring knowledge of which type of fault motion generates a tsunami.

    Step 2: Eliminate the strike-slip option

    'Ground shaking → strike-slip horizontal fault motion → tsunami' is incorrect because strike-slip motion displaces rock horizontally, not vertically, so it does not displace the water column and rarely generates a significant tsunami.

    Step 3: Eliminate the volcanic eruption option

    'Ground shaking → volcanic eruption → lahar' is incorrect because an earthquake does not directly trigger a volcanic eruption as the immediate next step in a tsunami cascade; this conflates two separate hazard chains.

    Step 4: Eliminate the storm surge option

    'Ground shaking → soil liquefaction → submarine landslide → storm surge' confuses a storm surge (a meteorological phenomenon) with a tsunami; a submarine landslide can trigger a tsunami but the chain as stated is physically inaccurate in labelling the final wave.

    Step 5: Select the correct answer

    'Ground shaking → vertical seafloor displacement → tsunami → coastal inundation and infrastructure destruction' is the only sequence that correctly identifies vertical dip-slip displacement as the mechanism linking the earthquake to tsunami generation.

  2. Question 2

    The 2011 Tōhoku earthquake generated a tsunami that travelled across the open Pacific at approximately 700 km/h before slowing dramatically near the Japanese coast. Using the shallow-water wave speed formula, what is the approximate depth of water d in which the wave was travelling at that speed? (Take g=9.8 m/s² and 1 km/h ≈ 0.278 m/s.)
    No clue? Show me the answer
    Correct answerCorrect!Incorrect
    AApproximately 3,800 m

    Step-by-step walkthrough

    Choose a solution method

    Method #1Direct Calculation

    Step 1: Identify the known values

    Wave speed v≈700 km/h. Converting: v=700×0.278≈194.6 m/s. The formula is v=gd​, where g=9.8 m/s².

    Step 2: Rearrange for depth

    Squaring both sides: v2=gd, so d=gv2​=9.8(194.6)2​=9.837,849​≈3,862 m.

    Step 3: Interpret the result

    A depth of approximately 3,800 m is consistent with average open-ocean depth in the Pacific, confirming that tsunami waves travel at very high speeds in deep water and slow dramatically as d decreases near the coast.

    Step 4: Select the correct answer

    The calculated depth of ~3,800 m matches the answer 'Approximately 3,800 m', which aligns with typical Pacific abyssal plain depths.

    Method #2Process of Elimination

    Step 1: Identify the calculation needed

    We need d=v2/g with v≈195 m/s and g=9.8 m/s², giving approximately 1952/9.8≈3,880 m.

    Step 2: Eliminate 1,200 m

    At 1,200 m depth: v=9.8×1200​=11760​≈108 m/s ≈390 km/h — far slower than 700 km/h, so this depth is too shallow.

    Step 3: Eliminate 7,500 m

    At 7,500 m: v=9.8×7500​=73500​≈271 m/s ≈975 km/h — faster than 700 km/h, so this depth is too great.

    Step 4: Eliminate 500 m

    At 500 m: v=9.8×500​=4900​=70 m/s ≈252 km/h — far too slow, ruling this out.

    Step 5: Select the correct answer

    Only approximately 3,800 m produces a wave speed consistent with 700 km/h, matching the deep-ocean conditions in which the Tōhoku tsunami travelled.

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