DP Chemistry · HL / SL · Reactivity 2. How much, how fast and how far?

R2.2 How fast? The rate of chemical change

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  1. Question 1

    A student monitors the decomposition of calcium carbonate with hydrochloric acid by recording the mass of the flask every 30 seconds. The following data are collected:

    Time / sMass / g
    085.00
    3084.76
    6084.58
    9084.46

    What is the mean rate of mass loss between 30 s and 90 s?

    No clue? Show me the answer
    Correct answerCorrect!Incorrect
    B0.0050 g s−1

    Step-by-step walkthrough

    Choose a solution method

    Method #1Approach 1

    Step 1: Identify the time interval and mass values

    The question asks for the mean rate between 30 s and 90 s. At t=30 s, mass =84.76 g; at t=90 s, mass =84.46 g.

    Step 2: Calculate the change in mass

    Δm=84.76−84.46=0.30 g The mass has decreased by 0.30 g over the interval.

    Step 3: Calculate the time interval

    Δt=90−30=60 s

    Step 4: Calculate the mean rate

    Mean rate=ΔtΔm​=600.30​=0.0050 g s−1

    Step 5: Select the correct answer

    The mean rate of mass loss between 30 s and 90 s is 0.0050 g s−1.

    Method #2Approach 2

    Step 1: Identify what is being calculated

    We need ΔtΔm​ between t=30 s and t=90 s, where Δm=0.30 g and Δt=60 s.

    Step 2: Eliminate 0.0025 g s⁻¹

    0.0025 g s−1 corresponds to 1200.30​, which uses an incorrect time interval of 120 s instead of 60 s. Eliminated.

    Step 3: Eliminate 0.0033 g s⁻¹

    0.0033 g s−1 would correspond to 900.30​, incorrectly using the endpoint time (90 s) rather than the interval length (60 s). Eliminated.

    Step 4: Eliminate 0.0040 g s⁻¹

    0.0040 g s−1 does not match any correct calculation of Δm/Δt using the given data. Eliminated.

    Step 5: Select the correct answer

    Only 0.0050 g s−1 equals 0.30÷60, the correct calculation. This is the answer.

  2. Question 2

    Consider the reaction: 2SO2​(g)+O2​(g)→2SO3​(g) The volume of the reaction container is halved while the temperature remains constant. Which statement correctly explains why the forward reaction rate increases?
    No clue? Show me the answer
    Correct answerCorrect!Incorrect
    CThe concentration of reactant molecules increases, resulting in a higher frequency of collisions.

    Step-by-step walkthrough

    Choose a solution method

    Method #1Approach 1

    Step 1: Identify the change being made

    Halving the volume at constant temperature doubles the pressure and therefore doubles the concentration of all gaseous species.

    Step 2: Link concentration to collision frequency

    According to collision theory, more particles occupying the same volume means they are closer together and collide more frequently per unit time.

    Step 3: Consider what stays the same

    Temperature is constant, so average kinetic energy does not change. Activation energy is an intrinsic property of the reaction and is also unchanged.

    Step 4: Select the correct statement

    The correct explanation is: concentration of reactant molecules increases, resulting in a higher frequency of collisions. This is the mechanism by which pressure increases the rate.

    Method #2Approach 2

    Step 1: Identify the change

    Halving the volume compresses the gases, increasing pressure and concentration at constant temperature.

    Step 2: Eliminate the activation energy option

    'The activation energy is reduced...' is incorrect — pressure changes do not alter Ea​. Only a catalyst can lower Ea​. Eliminated.

    Step 3: Eliminate the kinetic energy option

    'The average kinetic energy of the gas molecules increases...' is incorrect because temperature is held constant, so average kinetic energy is unchanged. Eliminated.

    Step 4: Eliminate the proportion of energetic particles option

    'A greater proportion of molecules now possess energy ≥ Ea​...' is incorrect — this describes the effect of a temperature increase, not a volume decrease at constant temperature. Eliminated.

    Step 5: Select the correct answer

    The remaining option — concentration of reactant molecules increases, resulting in higher collision frequency — correctly describes the effect of reduced volume at constant temperature.

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← Previous topicR2.1 How much? The amount of chemical changeNext topic →R2.3 How far? The extent of chemical change
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