DP Biology · HL / SL · C - Interaction and Interdependence

C2.2 Neural signalling

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  1. Question 1

    The table shows ion concentrations measured inside and outside a resting mammalian motor neuron.

    IonIntracellular (mmol dm⁻³)Extracellular (mmol dm⁻³)
    Na⁺15145
    K⁺1505

    Which mechanism is primarily responsible for maintaining the high intracellular concentration of K⁺ shown in the table?

    No clue? Show me the answer
    Correct answerCorrect!Incorrect
    CActive transport of K⁺ into the neuron by the sodium–potassium pump using ATP

    Step-by-step walkthrough

    Choose a solution method

    Method #1Approach 1

    Step 1: Identify what is being asked

    The question asks which mechanism is primarily responsible for maintaining the high intracellular K⁺ concentration (~150 mmol dm⁻³ inside vs. 5 mmol dm⁻³ outside) at rest.

    Step 2: Consider the concentration gradient

    K⁺ is at much higher concentration inside the neuron. This is against the K⁺ concentration gradient (which would push K⁺ outward), so passive diffusion alone cannot account for the high intracellular K⁺.

    Step 3: Recall the sodium–potassium pump

    The Na⁺/K⁺ pump uses ATP to actively transport 2 K⁺ ions into the cell for every 3 Na⁺ pumped out, working against the concentration gradient. This is the primary mechanism that builds up intracellular K⁺.

    Step 4: Select the correct answer

    The correct answer is active transport of K⁺ into the neuron by the sodium–potassium pump using ATP, as this directly and continuously maintains the high intracellular K⁺ concentration at rest.

    Method #2Approach 2

    Step 1: Identify what is being asked

    We need the mechanism that maintains high K⁺ inside the resting neuron, working against the outward concentration gradient.

    Step 2: Eliminate passive diffusion through the lipid bilayer

    Passive diffusion through the lipid bilayer is incorrect — ions are charged and cannot freely cross the hydrophobic core of the phospholipid bilayer without protein channels.

    Step 3: Eliminate voltage-gated K⁺ channels during repolarisation

    Voltage-gated K⁺ channels open during repolarisation actually allow K⁺ to flow out of the neuron, which would reduce — not maintain — the intracellular K⁺ concentration.

    Step 4: Eliminate attraction by negative interior charge

    While the negative interior does attract K⁺ inward (electrical gradient), this force is counteracted by the outward concentration gradient; it cannot alone account for maintaining the concentration difference against leak channels.

    Step 5: Select the correct answer

    Active transport by the sodium–potassium pump is the primary mechanism — it continuously pumps 2 K⁺ in per cycle at the cost of ATP, directly countering the outward K⁺ leak and maintaining the high intracellular concentration.

  2. Question 2

    During an action potential in a neuron, the membrane potential rapidly shifts from −70 mV to approximately +30 mV. Which ion movement is directly responsible for this depolarisation?
    No clue? Show me the answer
    Correct answerCorrect!Incorrect
    BNa⁺ flowing into the neuron through voltage-gated channels

    Step-by-step walkthrough

    Choose a solution method

    Method #1Approach 1

    Step 1: Identify the phase of the action potential

    The membrane potential rising from −70 mV to +30 mV describes depolarisation — the inside of the neuron becomes progressively more positive.

    Step 2: Apply knowledge of ion movement during depolarisation

    When threshold (−55 mV) is reached, voltage-gated Na⁺ channels open. Na⁺ has a high extracellular concentration and is attracted by the negative interior — both the concentration and electrical gradients drive Na⁺ into the cell.

    Step 3: Explain why this causes the observed change

    The rapid influx of positively charged Na⁺ ions makes the interior progressively more positive, shifting the potential from −70 mV up to approximately +30 mV.

    Step 4: Select the correct answer

    Na⁺ flowing into the neuron through voltage-gated channels is the direct cause of depolarisation during an action potential.

    Method #2Approach 2

    Step 1: Identify what is being asked

    We need the ion movement that makes the inside of the neuron change from −70 mV to +30 mV (i.e., become more positive).

    Step 2: Eliminate K⁺ flowing out

    K⁺ flowing out removes positive charge from inside the cell, which would make the interior more negative — this describes repolarisation, not depolarisation.

    Step 3: Eliminate Cl⁻ flowing in

    Cl⁻ flowing in would bring negative charge into the cell, making the interior more negative — this would cause hyperpolarisation, not depolarisation.

    Step 4: Eliminate Na⁺ being pumped out

    Na⁺ pumped out by the sodium–potassium pump removes positive charge, contributing to the resting potential — it does not cause the rapid depolarisation of an action potential.

    Step 5: Select the correct answer

    Only Na⁺ flowing into the neuron through voltage-gated channels introduces positive charge rapidly enough to shift the membrane from −70 mV to +30 mV.

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