Question 1
The table shows ion concentrations measured inside and outside a resting mammalian motor neuron.
Ion Intracellular (mmol dm⁻³) Extracellular (mmol dm⁻³) Na⁺ 15 145 K⁺ 150 5 Which mechanism is primarily responsible for maintaining the high intracellular concentration of K⁺ shown in the table?
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Correct answer
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IncorrectStep-by-step walkthrough
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Method #1Approach 1Step 1: Identify what is being asked
The question asks which mechanism is primarily responsible for maintaining the high intracellular K⁺ concentration (~150 mmol dm⁻³ inside vs. 5 mmol dm⁻³ outside) at rest.
Step 2: Consider the concentration gradient
K⁺ is at much higher concentration inside the neuron. This is against the K⁺ concentration gradient (which would push K⁺ outward), so passive diffusion alone cannot account for the high intracellular K⁺.
Step 3: Recall the sodium–potassium pump
The Na⁺/K⁺ pump uses ATP to actively transport 2 K⁺ ions into the cell for every 3 Na⁺ pumped out, working against the concentration gradient. This is the primary mechanism that builds up intracellular K⁺.
Step 4: Select the correct answer
The correct answer is active transport of K⁺ into the neuron by the sodium–potassium pump using ATP, as this directly and continuously maintains the high intracellular K⁺ concentration at rest.
Method #2Approach 2Step 1: Identify what is being asked
We need the mechanism that maintains high K⁺ inside the resting neuron, working against the outward concentration gradient.
Step 2: Eliminate passive diffusion through the lipid bilayer
Passive diffusion through the lipid bilayer is incorrect — ions are charged and cannot freely cross the hydrophobic core of the phospholipid bilayer without protein channels.
Step 3: Eliminate voltage-gated K⁺ channels during repolarisation
Voltage-gated K⁺ channels open during repolarisation actually allow K⁺ to flow out of the neuron, which would reduce — not maintain — the intracellular K⁺ concentration.
Step 4: Eliminate attraction by negative interior charge
While the negative interior does attract K⁺ inward (electrical gradient), this force is counteracted by the outward concentration gradient; it cannot alone account for maintaining the concentration difference against leak channels.
Step 5: Select the correct answer
Active transport by the sodium–potassium pump is the primary mechanism — it continuously pumps 2 K⁺ in per cycle at the cost of ATP, directly countering the outward K⁺ leak and maintaining the high intracellular concentration.
Question 2
During an action potential in a neuron, the membrane potential rapidly shifts from −70 mV to approximately +30 mV. Which ion movement is directly responsible for this depolarisation?No clue? Show me the answer
Correct answer
Correct!
IncorrectStep-by-step walkthrough
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Method #1Approach 1Step 1: Identify the phase of the action potential
The membrane potential rising from −70 mV to +30 mV describes depolarisation — the inside of the neuron becomes progressively more positive.
Step 2: Apply knowledge of ion movement during depolarisation
When threshold (−55 mV) is reached, voltage-gated Na⁺ channels open. Na⁺ has a high extracellular concentration and is attracted by the negative interior — both the concentration and electrical gradients drive Na⁺ into the cell.
Step 3: Explain why this causes the observed change
The rapid influx of positively charged Na⁺ ions makes the interior progressively more positive, shifting the potential from −70 mV up to approximately +30 mV.
Step 4: Select the correct answer
Na⁺ flowing into the neuron through voltage-gated channels is the direct cause of depolarisation during an action potential.
Method #2Approach 2Step 1: Identify what is being asked
We need the ion movement that makes the inside of the neuron change from −70 mV to +30 mV (i.e., become more positive).
Step 2: Eliminate K⁺ flowing out
K⁺ flowing out removes positive charge from inside the cell, which would make the interior more negative — this describes repolarisation, not depolarisation.
Step 3: Eliminate Cl⁻ flowing in
Cl⁻ flowing in would bring negative charge into the cell, making the interior more negative — this would cause hyperpolarisation, not depolarisation.
Step 4: Eliminate Na⁺ being pumped out
Na⁺ pumped out by the sodium–potassium pump removes positive charge, contributing to the resting potential — it does not cause the rapid depolarisation of an action potential.
Step 5: Select the correct answer
Only Na⁺ flowing into the neuron through voltage-gated channels introduces positive charge rapidly enough to shift the membrane from −70 mV to +30 mV.