DP Biology · HL / SL · B - Form and Function

B1.2 Proteins

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  1. Question 1

    A researcher measures the rate of hydrolysis of a peptide substrate by a protease isolated from a soil bacterium at various pH values. The highest rate is observed at pH 5.5, with activity declining sharply at pH 3 and pH 8. What is the most likely optimum pH range for this bacterial protease?
    No clue? Show me the answer
    Correct answerCorrect!Incorrect
    BBetween 5 and 6

    Step-by-step walkthrough

    Choose a solution method

    Method #1Approach 1

    Step 1: Identify what is being asked

    The question asks for the optimum pH range of the bacterial protease — the pH at which enzyme activity is highest.

    Step 2: Interpret the experimental data

    The highest rate of hydrolysis is observed at pH 5.5, with activity declining significantly below pH 3 and above pH 8. This pattern indicates the enzyme performs best near pH 5.5.

    Step 3: Match pH 5.5 to the correct range

    pH 5.5 falls within the range between 5 and 6. At this pH, the R-group ionisation states allow optimal ionic bond formation and active site geometry for catalysis.

    Step 4: Select the correct answer

    The optimum pH range is between 5 and 6, as this bracket contains pH 5.5 where maximum activity was recorded.

    Method #2Approach 2

    Step 1: Identify the question focus

    We need to identify which pH range best describes the optimum for this protease, given that peak activity occurs at pH 5.5.

    Step 2: Eliminate 'Between 2 and 3'

    Activity declines sharply at pH 3, meaning the region between 2 and 3 is far from the optimum. This option is eliminated.

    Step 3: Eliminate 'Between 7 and 8'

    Activity also declines sharply at pH 8, so the range 7–8 is on the descending portion of the activity curve, not the peak. This option is eliminated.

    Step 4: Eliminate 'Between 9 and 10'

    pH values above 8 are even further from the observed peak at 5.5, and highly alkaline conditions would severely alter R-group ionisation states. This option is eliminated.

    Step 5: Select the correct answer

    Between 5 and 6 is the only range that contains the observed peak activity at pH 5.5. This is the correct answer.

  2. Question 2

    A globular enzyme loses all catalytic activity when placed in a strongly acidic solution (pH 1.0). Which of the following best explains the molecular basis for this loss of activity?
    No clue? Show me the answer
    Correct answerCorrect!Incorrect
    CChanges in pH alter the protonation state of R-groups, disrupting ionic bonds and hydrogen bonds that maintain the enzyme's tertiary structure.

    Step-by-step walkthrough

    Choose a solution method

    Method #1Approach 1

    Step 1: Identify the relevant concept

    The question asks about the molecular mechanism by which extreme pH disrupts enzyme (protein) function — specifically how pH 1.0 causes loss of activity.

    Step 2: Apply knowledge of pH effects on R-groups

    At pH 1.0, excess H+ ions protonate R-groups: acidic R-groups (–COO⁻) gain protons and lose their negative charge, while basic R-groups (–NH₂) become –NH₃⁺. These charge changes alter the ionic interactions between R-groups.

    Step 3: Link R-group changes to structural disruption

    Ionic bonds (salt bridges) between oppositely charged R-groups are disrupted when those charges are removed or altered. Hydrogen bonding patterns also change. The tertiary structure — and therefore the active site geometry — is lost.

    Step 4: Select the correct answer

    The correct answer is that pH alters R-group protonation states, disrupting ionic bonds and hydrogen bonds that stabilise tertiary structure, causing denaturation and loss of function.

    Method #2Approach 2

    Step 1: Identify what to eliminate

    We need to find the option that correctly describes how pH (not temperature) disrupts protein structure at the molecular level.

    Step 2: Eliminate 'hydrolyses peptide bonds'

    Peptide bonds remain intact during denaturation — pH-induced denaturation disrupts non-covalent interactions and the 3D structure, not the primary sequence. This option is incorrect.

    Step 3: Eliminate 'increases kinetic energy, severing disulfide bonds'

    Increased kinetic energy is the mechanism for temperature-induced denaturation, not pH. Furthermore, disulfide bonds are covalent and the most resistant to disruption — they are not typically broken by pH changes. This option confuses two separate mechanisms.

    Step 4: Eliminate 'hydrophobic R-groups migrate to the surface'

    While hydrophobic interactions can be disrupted during denaturation, this is primarily a consequence of unfolding, not the primary molecular mechanism triggered by pH change. The causal explanation is incorrect here.

    Step 5: Select the correct answer

    Changes in pH alter the protonation state of R-groups, disrupting ionic bonds and hydrogen bonds is the correct mechanistic explanation for pH-induced denaturation.

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← Previous topicB1.1 Carbohydrates and lipidsNext topic →B2.1 Membranes and membrane transport
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