MYP 1 Chemistry · How Atoms Join Together · Updated

Covalent bonding

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  1. Question 1

    True or False: Small covalent molecules (for example, oxygen or water) melt at low temperatures because the covalent bonds inside each molecule are weak and break easily when heated.
    No clue? Show me the answer
    Correct answerCorrect!Incorrect
    BFalse

    Step-by-step walkthrough

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    Method #1Differentiating Intermolecular and Intramolecular Forces

    Step 1: Check what the statement is really claiming

    The sentence argues that simple covalent substances (such as water or oxygen) have low melting points because the covalent bonds inside their molecules are weak and easy to snap. To judge this properly, we must separate what holds atoms together within a molecule from what holds molecules together in a substance.

    Step 2: Separate bonds inside molecules from attractions between molecules

    In simple molecular substances there are two different kinds of forces to think about:

    1. Intramolecular forces: the covalent bonds joining atoms within one molecule. These are generally strong.
    2. Intermolecular forces: weaker attractions between nearby molecules (for instance, London dispersion forces or hydrogen bonding).

    Step 3: Link melting/boiling to what actually gets overcome

    When a simple molecular substance melts or boils, the molecules themselves stay intact—so we are not breaking the strong covalent bonds. The energy supplied is mainly used to overcome the intermolecular forces that keep molecules close together in the solid or liquid.

    Because those intermolecular forces are weak, only a small amount of heat is needed to separate the molecules, giving a low melting point.

    Step 4: Decide which option the reasoning rules out

    The claim is wrong because it blames low melting points on weak covalent bonds. Covalent bonds are strong; it is the weak forces between molecules that explain the low melting point. So the option that treats the statement as true should be rejected.

    Step 5: State the final judgement

    Since melting does not involve breaking covalent bonds and those bonds are not weak, the statement is false.

    Method #2Fact-checking Bond Strength

    Step 1: Identify the key idea to verify

    The statement claims that simple covalent substances (like or ) melt easily because the covalent bonds inside the molecules are weak and easy to break. To decide true/false, we should verify whether covalent bonds are actually weak.

    Step 2: Verify what a covalent bond is and how strong it is

    A covalent bond is the strong electrostatic attraction between a shared pair of electrons and the nuclei of the atoms involved.

    This means covalent bonds are typically very strong, and breaking them needs a lot of energy. If you broke the covalent bonds in water, you would be splitting hydrogen from oxygen—this is far more than simply turning ice into liquid water.

    Step 3: Explain why melting points can still be low

    So if covalent bonds are strong, why do many simple molecular substances have low melting points?

    During melting, the covalent bonds within each molecule remain unbroken. The change of state happens because we overcome the weak intermolecular forces between separate molecules. Since these forces are weak, only a small amount of energy is required, leading to low melting and boiling points.

    Step 4: Remove the option that matches the incorrect claim

    Because the statement incorrectly says low melting points are due to “weak covalent bonds,” it is not scientifically accurate. That means Option A should be eliminated.

    Step 5: Confirm which option must be correct

    Covalent bonds are strong, and low melting points in simple molecular substances are explained by weak intermolecular forces. Therefore, the statement is False.

  2. Question 2

    A student connects a solid copper wire into a simple circuit and notices the bulb lights up immediately. Which particles in the copper are able to move and carry the electric current through the wire?
    No clue? Show me the answer
    Correct answerCorrect!Incorrect
    CA ‘sea’ of delocalised electrons

    Step-by-step walkthrough

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    Method #1Direct Conceptual Recall

    Step 1: Work out what substance we are talking about

    The question is about conductivity in a solid copper wire. The key idea is to recognise copper as a metal. That means we should use what we know about Bonding, especially structure and bonding in metals, to explain how charge moves in it.

    Step 2: Bring to mind the model of metallic bonding

    In metallic bonding, a metal is pictured as a repeating lattice of positive metal ions (cations) with a surrounding ‘sea’ of delocalised valence electrons.

    These electrons are shared by the whole structure rather than belonging to one specific atom, so they can move through the solid.

    Step 3: Decide which charged particles can actually move

    Electrical conduction needs charged particles that are free to move.

    In solid copper:

    • The copper ions stay in fixed positions in the lattice, so they do not travel through the wire.
    • The delocalised electrons can drift through the metal when a potential difference (voltage) is applied.

    So, the delocalised electrons are the mobile charge carriers.

    Step 4: Rule out the choices that don’t fit

    Here is why the other answers don’t work:

    • Dissolved salts: They only help conduct in solutions (or melts) where ions can move, not inside a solid metal wire.
    • Copper ions (): These ions exist in the metallic lattice but are not free to flow through the solid.
    • Protons: Protons are in the nucleus and are not the particles that move to produce an electric current.

    Step 5: Choose the option that matches metallic conduction

    Using the metallic bonding idea, solid copper conducts because its delocalised valence electrons can move through the lattice and carry charge.

    Method #2Process of Elimination

    Step 1: Focus on what can move in a solid metal

    The question is asking which particles carry charge in a solid copper wire. With elimination, we think about which particles are genuinely mobile inside a solid metal lattice, from Bonding: Structure and bonding.

    Step 2: Cross off dissolved salts

    Dissolved salts conduct when their ions are free to move in an aqueous solution or a molten state. A solid copper wire isn’t a solution or a liquid, so there are no dissolved ions moving around. This option must be wrong.

    Step 3: Cross off protons

    Protons are trapped in the atom’s nucleus and held by very strong forces. They do not move during normal electrical conduction. If protons were moving through the wire, it would involve nuclear changes and the copper would no longer remain the same element.

    Step 4: Cross off copper ions

    Copper metal can be described as positive ions () in a fixed crystal lattice. In the solid, these ions can vibrate but cannot migrate through the wire to form a current. Ions only become mobile charge carriers when a substance is molten or dissolved.

    Step 5: The remaining option must be the charge carrier

    After eliminating the others, delocalised electrons are left. In metals, these outer electrons are not tied to individual atoms; they form a mobile ‘sea’ of negative charge that can drift through the solid lattice when a voltage is applied.

  3. Question 3

    A student compares why oxygen () and methane () are usually found as gases in the classroom, while many other substances are solids. What is the best scientific reason these simple covalent substances are gases at room temperature?
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    Correct answerCorrect!Incorrect
    Bthe attractions between separate molecules are very weak

    Step-by-step walkthrough

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    Method #1Direct Conceptual Application

    Step 1: Recognize what kind of substances $\text{O}_2$ and $\text{CH}_4$ are

    Substances such as oxygen () and methane () are classified as simple molecular covalent substances. That means they are made of small, separate molecules rather than a huge connected network.

    To explain why they are gases, we focus on what must happen when particles spread out during a change of state. This links ideas from Topic: Bonding and Topic: Matter.

    Step 2: Separate ‘bonds within a molecule’ from ‘forces between molecules’

    In these substances, there are two different kinds of attraction:

    1. Intramolecular bonds: the covalent bonds that strongly hold atoms together within each molecule.
    2. Intermolecular forces (IMFs): much weaker attractions that act between one molecule and another.

    When a liquid turns into a gas (boiling/evaporating), the molecules do not need to be torn apart into atoms. The energy supplied mainly overcomes the intermolecular forces, allowing whole molecules to separate and move freely.

    Step 3: Rule out statements about missing electrons or ‘no structure’

    Consider these options:

    • Option A cannot be right because atoms always contain electrons. Without electrons, covalent bonding would not be possible, and matter as we know it would not form.
    • Option C is also wrong because simple covalent molecules have definite shapes. For instance, has a specific tetrahedral geometry (explained using VSEPR), so it absolutely does have a defined structure.

    Step 4: Correct the idea that covalent bonds break easily

    Option D describes a common misunderstanding. Covalent bonds are generally strong. If covalent bonds were weak enough to break at room temperature, and would not remain as stable molecules—they would split into separate atoms.

    Because these substances exist as intact molecules at room temperature, we know the covalent bonds are not being broken. Their gaseous state must instead be explained by weak attractions between molecules.

    Step 5: Choose the explanation tied to weak intermolecular forces

    and are small, non-polar molecules, so the main attractions between their molecules are very weak (London dispersion forces).

    At room temperature, particles have enough thermal energy to overcome these weak intermolecular attractions, so the molecules spread out and move around as a gas. Therefore, the correct reason is that the forces between molecules are weak.

    Method #2Process of Elimination

    Step 1: Restate what the question is asking about $\text{O}_2$ and $\text{CH}_4$

    The question asks why simple covalent substances like oxygen () and methane () are gases at room temperature. We can find the correct choice by systematically removing options that conflict with basic chemistry facts.

    Step 2: Remove Option A (electrons are always present)

    Option A claims there are no electrons. From Atomic structure, we know every atom contains electrons. An oxygen atom has 8 electrons, and a methane molecule contains 10 electrons in total. Those electrons allow at least temporary attractions (London dispersion forces), so Option A is scientifically incorrect.

    Step 3: Remove Option C (simple molecules still have fixed geometry)

    Option C says there is no defined structure. But in Structure and bonding, we learn that molecules have specific shapes: oxygen is linear, and methane has a precise tetrahedral arrangement. Since their atoms are arranged in definite geometries, Option C must be wrong.

    Step 4: Remove Option D (covalent bonds are strong, not fragile)

    Option D suggests covalent bonds break easily at room temperature. That is incorrect: covalent bonds (inside a molecule) are strong. If they broke under everyday conditions, the molecules would not remain as and . During boiling/evaporation, molecules separate from each other while the covalent bonds stay intact.

    Step 5: Confirm Option B as the only correct explanation

    After eliminating A, C, and D, Option B remains. Simple molecular substances have low boiling points because the intermolecular forces between molecules are weak and need little energy to overcome. Room temperature provides enough energy for the molecules to stay far apart and move freely as a gas.

  4. Question 4

    In a covalent bond, two atoms share electrons. What name is given to how strongly one atom pulls on that shared pair compared with another atom?
    No clue? Show me the answer
    Correct answerCorrect!Incorrect
    DElectronegativity

    Step-by-step walkthrough

    Choose a solution method

    Method #1Direct Definition Recall

    Step 1: Focus on the key phrase in the definition

    You are being asked for the term that means an atom’s pull on a pair of electrons that is shared in a covalent bond. That wording points to a bonding property describing how atoms compete for the bonding electrons, which links to periodic trends in the Topic: Periodic table.

    Step 2: Rule out Polarity

    Polarity describes whether charge is unevenly spread in a bond or molecule. It can happen because atoms attract bonding electrons differently, but polarity is the outcome, not the term that names the ability to attract the shared electrons.

    Step 3: Rule out Electron Affinity

    Electron affinity refers to the energy change when a gaseous atom gains an extra electron to become a negative ion:

    This is about adding an electron to a single atom, not about pulling on a shared pair of electrons in a covalent bond.

    Step 4: Rule out Ionization Energy

    Ionization energy is the energy needed to remove an electron from a gaseous atom:

    That describes electron removal from an atom, which is different from attracting electrons that are being shared in a bond.

    Step 5: Select Electronegativity as the matching term

    From standard IUPAC/IB wording, electronegativity is the term for the relative strength with which an atom attracts the shared electron pair in a covalent bond. It is commonly compared using values such as the Pauling scale.

    Method #2Process of Elimination

    Step 1: Identify what the question is really asking for

    The wording points to a property describing an atom’s pull on a shared pair of electrons specifically when the atoms are joined by a covalent bond. So we can eliminate choices that describe energy changes for isolated atoms instead.

    Step 2: Remove Ionization energy from consideration

    Ionization energy is defined as the energy required to remove one mole of electrons from one mole of gaseous atoms.

    Because it deals with taking electrons away from separate atoms (not attracting a bonding pair), it does not fit and can be eliminated.

    Step 3: Remove Electron affinity from consideration

    Electron affinity is the energy change when an electron is added to a neutral gaseous atom to form a negative ion.

    Even though it involves attraction to an electron, it is about a lone atom gaining an electron, not two atoms sharing a pair in a covalent bond, so it can be ruled out.

    Step 4: Remove Polarity from consideration

    Polarity describes how charge is distributed across a bond (for example, whether a bond is polar covalent).

    Polarity happens because atoms have different pulls on electrons, but it names the bond’s uneven charge pattern, not the atom’s ability itself.

    Step 5: Confirm Electronegativity as the only suitable term

    After eliminating the other terms, Electronegativity remains. This is the accepted definition for the relative measure of how strongly an atom attracts the shared electron pair in a covalent bond.

    On the periodic table, scales such as the Pauling scale are used to compare electronegativities between elements.

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